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	<title>Comments on: Rigging, Leverage Formula and The &#8220;M&#8221;</title>
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	<link>http://www.maxrigging.com/rigging-leverage-formula-and-the-m</link>
	<description>how to get more out of your rowing, and rowing equipment</description>
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		<title>By: Mike</title>
		<link>http://www.maxrigging.com/rigging-leverage-formula-and-the-m/comment-page-1#comment-902</link>
		<dc:creator>Mike</dc:creator>
		<pubDate>Wed, 28 Oct 2009 02:14:37 +0000</pubDate>
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		<description>Hi Ian:

Darn good question, and something I&#039;ve been looking for myself. I&#039;ve tried with several physicists to develop one,
but no luck. I&#039;m not saying it is not out there, I just cannot find it . . . 

Hmm . . . anyone have a lead on this???</description>
		<content:encoded><![CDATA[<p>Hi Ian:</p>
<p>Darn good question, and something I&#8217;ve been looking for myself. I&#8217;ve tried with several physicists to develop one,<br />
but no luck. I&#8217;m not saying it is not out there, I just cannot find it . . . </p>
<p>Hmm . . . anyone have a lead on this???</p>
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	<item>
		<title>By: Ian</title>
		<link>http://www.maxrigging.com/rigging-leverage-formula-and-the-m/comment-page-1#comment-901</link>
		<dc:creator>Ian</dc:creator>
		<pubDate>Wed, 28 Oct 2009 02:01:30 +0000</pubDate>
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		<description>Mike,
Is there a formula available that WILL compare between different blade shapes?  I&#039;ve looked everywhere and can&#039;t find one.  Is there a way that we can derive blade surface area into the length value?</description>
		<content:encoded><![CDATA[<p>Mike,<br />
Is there a formula available that WILL compare between different blade shapes?  I&#8217;ve looked everywhere and can&#8217;t find one.  Is there a way that we can derive blade surface area into the length value?</p>
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	<item>
		<title>By: Mike</title>
		<link>http://www.maxrigging.com/rigging-leverage-formula-and-the-m/comment-page-1#comment-863</link>
		<dc:creator>Mike</dc:creator>
		<pubDate>Mon, 17 Aug 2009 02:37:40 +0000</pubDate>
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		<description>@Ali:

Two thoughts here. First, it would depend on the length of the oar blade, as I use approx 1/2 the length to find the &quot;M&quot;. Second, you cannot use this formula to compare the two types of blade design. It will not give you a valid comparison.</description>
		<content:encoded><![CDATA[<p>@Ali:</p>
<p>Two thoughts here. First, it would depend on the length of the oar blade, as I use approx 1/2 the length to find the &#8220;M&#8221;. Second, you cannot use this formula to compare the two types of blade design. It will not give you a valid comparison.</p>
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	<item>
		<title>By: Ali</title>
		<link>http://www.maxrigging.com/rigging-leverage-formula-and-the-m/comment-page-1#comment-862</link>
		<dc:creator>Ali</dc:creator>
		<pubDate>Tue, 11 Aug 2009 21:04:03 +0000</pubDate>
		<guid isPermaLink="false">http://www.maxrigging.com/?p=778#comment-862</guid>
		<description>How does the M value of the C2 Fat Smoothie sweep oar compare to that of the Smoothie2 with the vortex edge?</description>
		<content:encoded><![CDATA[<p>How does the M value of the C2 Fat Smoothie sweep oar compare to that of the Smoothie2 with the vortex edge?</p>
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